Home > Videos > Mathematics > Pre calculus > Limits > Proof: lim (sin x)/x

Solving Limits Calculus

Video title: Proof: lim (sin x)/x

An online precalculus video that teaches students about using the squeeze theorem to prove that the limit as x approaches 0 of (sin x)/x =1
Now Playing: Solving Limits Calculus
Khan Academy videos are licensed under a Creative Commons 3.0 License. This video is owned and provided free of cost by Khan Academy. Copyright Khan Academy 2010

Return to Topic
New members join now